Gravitation - Questions and Answers

Text Questions

Page 102 Questions

1. State the universal law of gravitation.

The universal law of gravitation states that every object in the universe attracts every other object with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The force acts along the line joining the centers of the two objects.

Mathematically: F = G × (m₁ × m₂) / d²

Where F is the gravitational force, G is the universal gravitational constant, m₁ and m₂ are the masses of the two objects, and d is the distance between their centers.

2. Write the formula to find the magnitude of the gravitational force between the earth and an object on the surface of the earth.

The formula to find the magnitude of gravitational force between the earth and an object on its surface is:

F = G × (M × m) / R²

Where:
F = gravitational force (weight of the object)
G = universal gravitational constant (6.67 × 10⁻¹¹ N m²/kg²)
M = mass of the earth (6 × 10²⁴ kg)
m = mass of the object
R = radius of the earth (6.4 × 10⁶ m)

This force is also equal to the weight of the object: F = m × g, where g = G × M / R² ≈ 9.8 m/s²

Page 104 Questions

1. What do you mean by free fall?

Free fall is the motion of an object under the influence of gravitational force only. Whenever objects fall towards the earth under gravitational force alone, without any other force acting on them (like air resistance), they are said to be in free fall.

2. What do you mean by acceleration due to gravity?

Acceleration due to gravity is the acceleration experienced by an object when it falls freely under the influence of the earth's gravitational force. It is denoted by 'g' and has a value of approximately 9.8 m/s² on the surface of the earth. This acceleration is always directed towards the center of the earth.

Page 106 Questions

1. What are the differences between the mass of an object and its weight?

The main differences between mass and weight are:

  • Mass is the amount of matter in an object, while weight is the force with which the earth attracts that object.
  • Mass is a scalar quantity (has only magnitude), while weight is a vector quantity (has both magnitude and direction).
  • Mass remains constant everywhere, while weight changes with location (due to variation in 'g').
  • The SI unit of mass is kilogram (kg), while the SI unit of weight is newton (N).
2. Why is the weight of an object on the moon 1/6th of its weight on the earth?

The weight of an object on the moon is 1/6th of its weight on the earth because:

  • The mass of the moon is much smaller than that of the earth.
  • The radius of the moon is smaller than that of the earth.
  • According to the universal law of gravitation, weight W = G × M × m / R², where M is the mass of the celestial body and R is its radius.
  • Due to the combination of the moon's smaller mass and smaller radius, the gravitational acceleration on the moon (g_m) is about 1/6th of that on earth (g_e).

Page 109 Questions

1. Why is it difficult to hold a school bag having a strap made of a thin and strong string?

It is difficult to hold a school bag with thin straps because pressure = force/area. When the strap is thin, the area of contact with the shoulder is small. For the same weight (force), a smaller area results in greater pressure on the shoulder, making it uncomfortable and difficult to carry.

2. What do you mean by buoyancy?

Buoyancy is the upward force exerted by a fluid (liquid or gas) on an object immersed in it. This upward force is called buoyant force or upthrust. It occurs because the pressure at the bottom of the immersed object is greater than the pressure at the top, resulting in a net upward force.

3. Why does an object float or sink when placed on the surface of water?

An object floats or sinks in water based on the relative densities of the object and water:

  • If the density of the object is less than that of water, the buoyant force is greater than the weight of the object, so it floats.
  • If the density of the object is greater than that of water, the buoyant force is less than the weight of the object, so it sinks.
  • If the density of the object is equal to that of water, the object remains suspended at any depth.

Page 110 Questions

1. You find your mass to be 42 kg on a weighing machine. Is your mass more or less than 42 kg?

The weighing machine actually measures weight, not mass. It converts weight to mass using the standard value of g (9.8 m/s²). If the actual value of g at your location is different from 9.8 m/s², then your actual mass would be different from 42 kg. However, for most practical purposes, we can consider the measured value as your mass.

2. You have a bag of cotton and an iron bar, each indicating a mass of 100 kg when measured on a weighing machine. In reality, one is heavier than other. Can you say which one is heavier and why?

The iron bar is actually heavier than the bag of cotton. This is because:

  • Both show the same mass (100 kg) on the weighing machine, which means they have the same weight at that location.
  • However, cotton, being less dense, displaces more air and experiences greater buoyant force from air.
  • In vacuum (where there is no buoyant force), the iron bar would weigh more than the cotton.
  • So in reality, the iron bar has more actual mass than the cotton.

Exercise Questions

1. How does the force of gravitation between two objects change when the distance between them is reduced to half?

According to the universal law of gravitation, F ∝ 1/d². If the distance is reduced to half (d' = d/2), then:

F' ∝ 1/(d/2)² = 1/(d²/4) = 4/d²

Therefore, F' = 4F

The gravitational force becomes 4 times the original force when the distance is reduced to half.

2. Gravitational force acts on all objects in proportion to their masses. Why then, a heavy object does not fall faster than a light object?

Although gravitational force is proportional to mass (F ∝ m), acceleration is given by a = F/m. So:

a = F/m = (G M m / d²) / m = G M / d²

This shows that acceleration due to gravity is independent of the mass of the falling object. Therefore, all objects, regardless of their mass, fall with the same acceleration in the absence of air resistance.

3. What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10²⁴ kg and radius of the earth is 6.4 × 10⁶ m.)

Using the formula F = G M m / R²:

F = (6.7 × 10⁻¹¹ N m² kg⁻² × 6 × 10²⁴ kg × 1 kg) / (6.4 × 10⁶ m)²

F = (4.02 × 10¹⁴) / (4.096 × 10¹³) = 9.8 N

The gravitational force between earth and 1 kg object on its surface is 9.8 N.

4. The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is greater or smaller or the same as the force with which the moon attracts the earth? Why?

The earth attracts the moon with the same force as the moon attracts the earth. According to Newton's third law of motion, forces always occur in equal and opposite pairs. The gravitational force between two bodies is equal in magnitude but opposite in direction.

5. If the moon attracts the earth, why does the earth not move towards the moon?

Although the moon attracts the earth with the same force as the earth attracts the moon, the earth does not move significantly toward the moon because:

  • The earth has much greater mass than the moon.
  • According to Newton's second law (F = ma), for the same force, acceleration is inversely proportional to mass.
  • The acceleration produced in the earth is very small compared to the acceleration produced in the moon due to the earth's much larger mass.
  • Actually, both bodies move towards each other, but the earth's movement is negligible compared to the moon's movement.
6. What happens to the force between two objects, if
(i) the mass of one object is doubled?
(ii) the distance between the objects is doubled and tripled?
(iii) the masses of both objects are doubled?

(i) If mass of one object is doubled: F ∝ m, so force becomes 2F (doubled)

(ii) If distance is doubled: F ∝ 1/d², so force becomes F/4 (one-fourth)
If distance is tripled: F ∝ 1/d², so force becomes F/9 (one-ninth)

(iii) If masses of both objects are doubled: F ∝ m₁m₂, so force becomes 4F (four times)

7. What is the importance of universal law of gravitation?

The universal law of gravitation is important because:

  • It explains the force that binds us to the earth.
  • It explains the motion of the moon around the earth.
  • It explains the motion of planets around the Sun.
  • It explains the tides due to the moon and the Sun.
  • It helps in understanding the behavior of celestial bodies in the universe.
8. What is the acceleration of free fall?

The acceleration of free fall is the acceleration experienced by an object when it falls freely under the influence of gravitational force alone. On earth, this acceleration is approximately 9.8 m/s² and is denoted by 'g'.

9. What do we call the gravitational force between the earth and an object?

The gravitational force between the earth and an object is called the weight of the object.

10. Amit buys few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not, why? [Hint: The value of g is greater at the poles than at the equator.]

No, the friend will not agree with the weight of gold bought. This is because:

  • The value of g is greater at the poles than at the equator.
  • Weight = mass × g, so for the same mass of gold, the weight is greater at the poles.
  • When measured at the equator, the same gold will show less weight.
  • Therefore, the friend at the equator will think that Amit bought less gold.
11. Why will a sheet of paper fall slower than one that is crumpled into a ball?

A sheet of paper falls slower than a crumpled paper ball because:

  • The sheet of paper has larger surface area, so it experiences more air resistance.
  • The crumpled ball has smaller surface area, so it experiences less air resistance.
  • In vacuum (without air resistance), both would fall at the same rate.
12. Gravitational force on the surface of the moon is only 1/6 as strong as gravitational force on the earth. What is the weight in newtons of a 10 kg object on the moon and on the earth?

Mass of object, m = 10 kg

On earth: Weight = m × g = 10 kg × 9.8 m/s² = 98 N

On moon: Weight = (1/6) × weight on earth = (1/6) × 98 N = 16.33 N

13. A ball is thrown vertically upwards with a velocity of 49 m/s.
Calculate
(i) the maximum height to which it rises,
(ii) the total time it takes to return to the surface of the earth.

Initial velocity, u = 49 m/s
Final velocity at maximum height, v = 0 m/s
Acceleration due to gravity, g = -9.8 m/s² (negative as it opposes motion)

(i) Using v² = u² + 2as
0 = (49)² + 2 × (-9.8) × h
0 = 2401 - 19.6h
19.6h = 2401
h = 2401 / 19.6 = 122.5 m

(ii) Using v = u + at for upward motion
0 = 49 - 9.8t
9.8t = 49
t = 49 / 9.8 = 5 s (time to reach maximum height)
Total time = 2 × 5 = 10 s (time up + time down)

14. A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.

Height, h = 19.6 m
Initial velocity, u = 0 m/s
Acceleration due to gravity, g = 9.8 m/s²

Using v² = u² + 2gh
v² = 0 + 2 × 9.8 × 19.6
v² = 19.6 × 19.6
v = √384.16 = 19.6 m/s

The final velocity just before touching the ground is 19.6 m/s.

15. A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s², find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Initial velocity, u = 40 m/s
Final velocity at maximum height, v = 0 m/s
Acceleration due to gravity, g = -10 m/s²

Using v² = u² + 2as
0 = (40)² + 2 × (-10) × h
0 = 1600 - 20h
20h = 1600
h = 1600 / 20 = 80 m

Maximum height reached = 80 m
Net displacement = 0 (returns to starting point)
Total distance covered = 80 m (up) + 80 m (down) = 160 m

16. Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth = 6 × 10²⁴ kg and of the Sun = 2 × 10³⁰ kg. The average distance between the two is 1.5 × 10¹¹ m.

Using F = G M₁ M₂ / d²
F = (6.7 × 10⁻¹¹ × 6 × 10²⁴ × 2 × 10³⁰) / (1.5 × 10¹¹)²
F = (8.04 × 10⁴⁴) / (2.25 × 10²²)
F = 3.57 × 10²² N

The gravitational force between earth and Sun is 3.57 × 10²² N.

17. A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.

Let the stones meet after time t at height h from ground.

For falling stone:
Distance travelled = 100 - h
Using s = ut + ½gt²
100 - h = 0 × t + ½ × 9.8 × t²
100 - h = 4.9t² ...(1)

For upward thrown stone:
Distance travelled = h
Using s = ut + ½gt² (g = -9.8 m/s²)
h = 25t - ½ × 9.8 × t²
h = 25t - 4.9t² ...(2)

Adding equations (1) and (2):
100 - h + h = 4.9t² + 25t - 4.9t²
100 = 25t
t = 4 s

From equation (2):
h = 25 × 4 - 4.9 × (4)²
h = 100 - 4.9 × 16
h = 100 - 78.4 = 21.6 m

The stones meet after 4 seconds at a height of 21.6 m from the ground.

18. A ball thrown up vertically returns to the thrower after 6 s. Find
(a) the velocity with which it was thrown up,
(b) the maximum height it reaches, and
(c) its position after 4 s.

Total time of flight = 6 s
Time to reach maximum height = 6/2 = 3 s

(a) Using v = u + at at maximum height
0 = u - 9.8 × 3
u = 29.4 m/s

(b) Using v² = u² + 2as
0 = (29.4)² + 2 × (-9.8) × h
19.6h = 864.36
h = 864.36 / 19.6 = 44.1 m

(c) After 4 s, the ball is on its way down
Time from top = 4 - 3 = 1 s
Distance from top = ½ × 9.8 × (1)² = 4.9 m
Position from ground = 44.1 - 4.9 = 39.2 m

19. In what direction does the buoyant force on an object immersed in a liquid act?

The buoyant force on an object immersed in a liquid acts vertically upward, opposite to the direction of gravity.

20. Why does a block of plastic released under water come up to the surface of water?

A block of plastic released under water comes up to the surface because:

  • The density of plastic is less than that of water.
  • The buoyant force acting on the plastic is greater than its weight.
  • This net upward force causes the plastic to rise to the surface.
21. The volume of 50 g of a substance is 20 cm³. If the density of water is 1 g cm⁻³, will the substance float or sink?

Density of substance = mass/volume = 50 g / 20 cm³ = 2.5 g/cm³

Density of water = 1 g/cm³

Since density of substance (2.5 g/cm³) > density of water (1 g/cm³), the substance will sink in water.

22. The volume of a 500 g sealed packet is 350 cm³. Will the packet float or sink in water if the density of water is 1 g cm⁻³? What will be the mass of the water displaced by this packet?

Density of packet = mass/volume = 500 g / 350 cm³ = 1.43 g/cm³

Density of water = 1 g/cm³

Since density of packet (1.43 g/cm³) > density of water (1 g/cm³), the packet will sink in water.

When the packet is fully immersed, it will displace water equal to its own volume (350 cm³).

Mass of water displaced = volume × density = 350 cm³ × 1 g/cm³ = 350 g